Help with my three digit sums and products code.

[mmoreno33]

Hi, I am in need of some quick help with my code. It is supposed to test all three digit numbers for when the sum and product of the individual digits are equal. When I run it as is, it just repeatedly prints 123 (which is the first of the 3 digit numbers to satisfy the conditions). a,b, and c are representing each digit of the number with i representing each the number being tested. All help and advice appreciated! Thank you in advance!

#include <iostream>
using namespace std;
int main()
{
int i;
int sum = 0;
int product = 0;

for (i=100; 100<=i<999; i++) {
	int a = i / 100;
	int b = i % 10;
	int c = (i / 10) % 10; 
	sum = a + b + c;
	product = a * b * c;
	while(sum==product) {
		cout << i << endl;
	}
}
return 0;
}

[Yatora]

Can you give us some examples? I don't understand what you say.

[mmoreno33]

Sorry, this is probably poorly coded. However what I'm trying to accomplish is to print the numbers that would satisfy these conditions. For example, 123 would work because:
1+2+3=6
and
1*2*3=6.

[Yatora]

Could you please give some more examples? One example doesn't cut it.

[mmoreno33]

Sorry about that. It is looking for when the product and sum of the three individual digits are the same.
132: 1+3+2=6, and 1*3*2=6, and 6=6.
231: 2+3+1=6, and 2*3*1=6, and 6=6.

I'm sorry, I'd give more examples but I don't know that there are more than just ones whose digits are 1, 2 and 3.

But what it is supposed to do is print the numbers that have an equal product and sum like the above examples do.

[jonnin]

while(sum==product) {
cout << i << endl;

This loops forver because the 2 values in the loop condition never change.
this should be an if statement.

[mmoreno33]

that did it! thank you!