Comparison between integers and pointers?

[TheBeginner]

This is just supposed to see if what the second character of what the user enters is "x".

string c;
cout << "";
cin >> c;
if (c[1]=="x") //error here 

Output says:

41 C:\Users\Jim\Documents\test.cpp ISO C++ forbids comparison between pointer and integer 

[tummychow]

Hm, try single quotes.

[TheBeginner]

Thanks, tummy!

[tummychow]

Welcome.

[mulpro]

Hm, try single quotes.

Right, "x" is a string literal, which the compiler sees as an array of characters, or 'x' and 0 or '/0'.
So you're comparing a single character constant to a temporary multi-character array. Single quotes indicate single character constants.

[TheBeginner]

Thanks for the info, mulpro.

[mulpro]

NP, it's also worth noting that the compiler converts both character literals like 'x' and '\0' and string literals like "hello" to their ascii numerical equivalents. So the compiler warning you of a comparison between an integer and pointer shows you how the compiler sees the expression c[1] == "x", it converts the string character element c[1] to an integer, and the string literal "x" to a pointer to two integer values (an array), 120 and 0.