what does #IND mean ?

[ysf007]

Dear community,

what -1.#IND means ?

  cout <<u[0]/abs(v[0])<< " ^ " <<(1/beta)<<" = "<<pow((u[0]/abs(v[0])),(1/beta))<< endl;

I'm getting this output
0.361351 ^ 0.666667 = -1.#IND

[48T7M4Gy]

http://stackoverflow.com/questions/7476177/why-the-return-value-of-double-is-1-ind

[Golden Lizard]

IND=indefined a.k.a NaN (not a number)

[JayhawkZombie]

Nit: IND = indeterminate.

[L1vUM4Gy]

How about this?
cout << "0.361351 ^ 0.666667 = " << pow (0.361351, 0.666667) << endl;

0.361351 ^ 0.666667 = 0.507325