IF statements inside FOR loop

[ash54546]

I'm trying to write a program that reads in a users input and iterates through it and finds a certain word. If that word is found, do something. Quite simple actually.

  FOR (i; i <string; i++)
     IF string contains "example"
        //do something
     ELSE 
        //do something 

I was wondering how in the //do something, I could put another function that I've written BUT that would just cause my program to run that function i amount of times instead of just once. How do I get around this? Cant seem to figure it out.

Thanks!

[Golden Lizard]

You use break.

for example:

for(i=0; i<value; ++i)
   if(my_array[i]==10) break; //goes out of loop 

[xismn]

#include <string>

void my_function() {
	//...
}

int main() {

	std::string string_input = "this is an example.";
	std::string string_search = "example";

	std::string::size_type pos = string_input.find(string_search);
	if (pos != std::string::npos) {
		
		const int number_of_iterations = 10;
		for (int i = 0; i < number_of_iterations; ++i) {
			my_function();
		}

	}

	return 0;
}

[ash54546]

Cool. That seemed to work. Another issue though. I currently have:

 FOR (i; i <string; i++)
     IF string contains "example"
        FOR (i; i <string; i++)
             IF string contains "2nd example"
                  //do something
             ELSE 
                  //do something
      ELSE
           //do something

Even if the example or 2nd example is found, the "ELSE" is always executed. Why?

[fantomasAlbania]

Because you wrote the same for loop and your string value is the same as long as for loop will be working. You are not writting the code well I think.

Another thing you have not wrote well is that , an int can not be compared with a string type .

for(int i =0; i < string; i++)

Secondly, you have to write the example code if you want to get an answer.