"cout"ing the sum of 2 arrays

[DCNOS18]

Write your question here.

Hi, I have an assignment for my college class that I just can't wrap my head around. Here is the assignment that I am struggling with.

1. Ask user to enter 3 numbers a, b and c. Write a program, which will print the values of
following expressions:
a.
max(a,a+b,a-c) + max(b,2b-c,b+2a)
b.
max(3,c+3a,0) + min(ab-2,3c,ac)
Define functions max and min, which will accept 3 numbers as arguments and return the max
and min of them correspondingly. Use these function in order to calculate the values of the
expressions.

I understand that I have to use arrays, add them together, and then display the result of them, but I don't have the slightest clue about how to do that. So far I have been able to calculate the max from an array, but that's about it. If someone could at least point me in the right direction, it would be greatly appreciated!

  #include "stdafx.h"
#include <iostream>

using namespace std;

int main()
{

	
	int a[3], i, max;

	for (i = 0; i<3; i++)
	{
		cin >> a[i];
		if (i == 0) max = a[i];
		if (a[i]>max) max = a[i];
		
	}
	cout << "max numb is: " << max <<  endl;
    return 0;
}

[dragonStarN]

1. Ask user to enter 3 numbers a, b and c.

You need to do that first. There is nothing that asks the user to enter 3 numbers.

[integralfx]

const int SIZE = 3;
int max( int a, int b, int c )
{
    int nums[SIZE] = { a, b, c };

    int max = nums[0];
    for( int i = 1; i < SIZE; i++ ) {
        // ...
    }
}