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[zeroblank]

What's wrong with this simple line of code

  cout<<("%c","a"-32)<<endl;

[E0p9LyTq]

C++ std::cout is not C printf(). std::cout doesn't use output format strings.

[zeroblank]

even when i did

 cout<<"a"-32<<endl;

it gave me the same results

[cire]

"a" is a string literal which degenerates into a pointer-to-const-char. You are not subtracting 32 from the character 'a'. You are subtracting 32 from the address where the nul-terminated string "a" is stored.

cout << (char)('a' - 32) << '\n' ;

Single and double quotes mean different things in C++.

[zeroblank]

thank you