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//This program takes two times (each in 12 hour cycle) and returns difference in Seconds.
int main(){
int Hour, Minute, Second;
int Time1, Time2;
cout<<"Enter the first time in hours, minutes, and seconds: ";
cin>>Hour>>Minute>>Second;
Time1 = Time_In_Seconds (Hour, Minute, Second);
cout<<"Enter the second time in hours, minutes, and seconds: ";
cin>>Hour>>Minute>>Second;
Time2 = Time_In_Seconds (Hour, Minute, Second);
cout<<Time1- Time2<<endl; //If Time2 is larger I get a negative number. Is there a way to get a correct answer regardless
//of which time is larger? I used an if statement to solve this, but I am curious if there is another smarter way to do it.
// Thanks for your help.
if (Time1 > Time2)
cout<<"The time in seconds between two times is "<<Time1 - Time2<<endl;
else
cout<<"The time in seconds between two times is "<<Time2 - Time1<<endl;
return 0;
}
int Time_In_Seconds (int hour, int min, int sec){
int Time_in_Sec;
Time_in_Sec = ((hour *60 *60) + (min *60) + sec);
return Time_in_Sec;
}
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