Passing function name in command line argument

[chocoluve]

How do I pass an argument value from the command line as a file name?

For example, if argv[1] contains the text "transplantPatient.txt"

would the code for declaring this be:

ifstream ArgFile;
ArgFile.open(argv[1]);

Thanks

[SamuelAdams]

This opens a file and displays the line number and line from file using argv[1].

// New template, do not delete

#include <iostream>
#include <fstream>
#include <string>
using namespace std;

int main(int argc, char** argv) {

// Read from file
string line;
int count=0;
ifstream InFile (argv[1]);
if (InFile.is_open())
	{
	while ( getline (InFile,line) )
		{
		count++;
		cout << count << " "<< line << '\n';
		}
	InFile.close();
	}
else 
	{
	cout << " Unable to open file" << endl;
	return 1;
	}

return 0;
}

[ybf3AqkS]

You can also use argc to check how many command line arguments there are, if it's just a filename then argc will be 2.