Question on Arrays

[CTLZ]

When you enter data into an array via prompt, will it overwrite the data within the array if u call the function again, eventhough u never close the program ?

[Moschops]

If you have a variable, and you write a value to it, and then you write different data into the exact same variable, the original data is replaced with the new data.

#include <iostream>
int main()
{
  int x;
  std::cin >> x;  // user enters a value
  std::cout << x; // show the value the user entered

  std::cin >> x; // user enters a different value
  std::cout << x; // the value changed
}

[Yawzheek]

I'm not sure I completely understand your question, but it sounds the same as Moschops describes. If you pass an array to a function that writes to it, then call the same function with the same array again, it will write over the data you previously input:

#include <iostream>

using namespace std;

void i_array_in(int* i_arr)
{
	for (size_t i = 0; i != 3; ++i) cin >> i_arr[i];
}

void i_array_out(int* i_arr)
{
	for (size_t i = 0; i != 3; ++i) cout << i_arr[i] << ' ';
	cout << endl;
}

int main()
{
	int i_array[3];
	cout << "Enter three integers: ";
	i_array_in(i_array);
	i_array_out(i_array);
	cout << "Enter three DIFFERENT integers: ";
	i_array_in(i_array);
	i_array_out(i_array);

    return 0;
}

If you run that code with 1 2 3, then run it again with 4 5 6, you'll see that the program never closed, we passed the same array to our read in function twice, but it will write over our first three integers with three new integers.