int main() versus void main()

[chrisname]

Oh, I forgot about operator preference.

Tbh, the script above (three line one) is what I used to build that; so I know it evaluates to zero.

[Disch]

wait a minute... I didn't actually compile it... but there's no way...

*does math*

Apparently I suck at math.

For some reason I didn't make the connection that 16 + 8 = 24

I lose!

[chrisname]

Lol!

[gcampton]

wtf. You guys fail at math.

return 42/42; // hhgttg beats your silly XOR

This evaluates to 1, not zero

Bahahahaha, WOW, well it was 1:03am when I posted that....
I might as well just put return 42; then eh.

[Duthomhas]

This returns nothing:

#include <iostream>
int main()
  {
  int z = 0;
  std::cout << "Hello world!\n";

  return 42/z;
  }

:0)

[tummychow]

Or maybe it just breaks the universe.

[gcampton]

I assume by nothing you mean 0.

Line 7 warning: division by zero;

[gcampton]

weird, I just did return 42/0; got a warning for dividing by 0;
then did:

int a=0;
return 42/a;

and it compiles fine

running it however...

Process terminated with status -1073741676

return 42/0;
gives the same status. -1073741676

However:
return 0/42;
terminates program with status 0

[tummychow]

There must be an exception for div by 0. Is there?

[firedraco]

Using VC++ it throws an "exception" (not really an exception but you can catch it for some reason).

[helios]

However:
return 0/42;
terminates program with status 0

Herp derp.
0/x=0

[gcampton]

Herp derp.
0/x=0

yeah so what is:
x/0= ?
I don't get why it works one way but not the other.

[tummychow]

Assuming x does not equal zero, of course. 0/0 is undefined, as is any value / 0. That's just how it is.
Based on a limit of any number / x, with x approaching zero, the limit should reach infinity. However, that doesn't define divbyzero.

[Duthomhas]

Technically, it does return something -- just what is returned depends on your operating system. Many have a way of indicating program failure, such as an abort due to a hardware exception.

[helios]

Based on a limit of any number / x, with x approaching zero, the limit should reach infinity.

The proper way to say is: the limit of |a|/x is +∞ as x approaches 0 from the right, and -∞ as x approaches 0 from the left.

Technically, it does return something

I was talking about the function, not the program.

[Duthomhas]

I was talking about the program, not the function. :-)
I was responding to gcampton

[chrisname]

There must be an exception for div by 0. Is there?

CPU exception 0x00 is "Division by zero" error; see chapter 6, volume 3a: http://www.intel.com/products/processor/manuals/

[M364M4Ncro]

i made a program using void main() that features looping on a XP, and tried to run it on a win7, but after 2-3 loopings the program closes, then i changed the void main() into int main() with return 0; and now it works fine and i may loop it as much as i want w/o closing it itself

so yeah, dont use void main()

[helios]

i made a program using void main() [...] but after 2-3 loopings the program closes

I seriously doubt it has anything to do with it.

[chrisname]

That's impossible, having void as a return value could not cause that problem...