How do I Output only One Number Instead of Multiple in a Loop

[ZSquared]

I am writing a program that does multiple things. For the last part I need to output the sum of the squares of all the odd numbers between two numbers that the user inputs earlier in the program.

  		//sum of squared odd numbers between firstNum and secondNum
		for (number = firstNum; number <= secondNum; number++)
		{
			if (number % 2 != 0)
			{
				sum = sum += pow(number, 2);
				cout << "\nThe sum of the squares of all odd numbers between " << firstNum << " and " << secondNum << " is: " << sum << endl;
			}
		}

Everything works, I get the correct answer at the end and everything, however the output lists each step individually rather than one whole number i.e:

"The sum of the squares of all odd numbers between 2 and 14 is: 9"

"The sum of the squares of all odd numbers between 2 and 14 is: 34"

"The sum of the squares pf all odd numbers between 2 and 14 is: 83" etc. etc.

Where what is happening is it first shows 3^2, then it shows 3^2+5^2, then 3^2+5^2+7^2, all the way up until the end of the loop. I still get the correct answer however i just want it to show the final answer not all of the steps leading up to it.

Thank you,
ZSquared

[TarikNeaj]

If you want it to only print out the final answer, and not each step, couldn't you simply move it outside of the loop?

//sum of squared odd numbers between firstNum and secondNum
		for (number = firstNum; number <= secondNum; number++)
		{
			if (number % 2 != 0)
			{
				sum = sum += pow(number, 2);
				
			}
		}
             cout << "\nThe sum of the squares of all odd numbers between " << firstNum << " and " << secondNum << " is: " << sum << endl;

[ZSquared]

That did the trick! I had actually thought of that, but I must have only put it outside of the if statement rather than the entire for loop. Thanks for the help even though it was something so simple!

[TarikNeaj]

My pleasure, Goodluck^^