Transpose 2 2d dynamic array

[Lado]

I´m writing a void function to transpose a matrix and this is what I have:

[Nico]

Have a look at the output of this code. I think you will find that your matrix is transposed but the result is last when you delete the temporary "trans" variable.

#include <iostream>

using namespace std;

int** myArray;

void print(int** arr, int row, int col)
{
    for(int y=0; y < row; y++)
    {
        for(int x=0; x < col; x++) cout << arr[x][y];
        cout << endl;
    }
}

void transpose(int** arr, int row, int col)
{
    int** trans=new int *[col];
    for(int i=0; i < col; i++)
    {
        trans[i]=new int[row];
    }
    for(int i=0; i < col; i++)
    {
        for(int j=0; j < row; j++)
        {
            trans[i][j]=arr[j][i];
        }
    }
    print(trans, 2, 2);
    for(int i=0; i < col; i++)
    {
        delete[] trans[i];
    }
    delete[] trans;
}

int main(int argc, char** argv)
{
    int** myArray=new int *[2];
    for(int i=0; i < 2; i++)
    {
        myArray[i]=new int[2];
    }
    myArray[0][0] = 0;
    myArray[0][1] = 1;
    myArray[1][0] = 2;
    myArray[1][1] = 3;

    print(myArray, 2, 2);
    cout << endl;
    transpose(myArray, 2, 2);
    cout << endl;
    print(myArray, 2, 2);
    return 0;
}