Rounding numbers
How would you round a positive number number to the nearest hundred?
Here is what I came up with:
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#include <iostream>
using namespace std;
int main(){
int cinValue;
cout << "Please enter a value: " << endl;
cin >> cinValue;
int roundOff = cinValue % 100;
int finalVar = cinValue - roundOff;
cout << "Rounded to the nearest hundredth: " << finalVar << endl;
return 0;
}
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Thank You
Problem with orangepeel367's solution is that it always rounds down.
Please enter a value:
199
Rounded to the nearest hundredth: 100
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To fix this, simply add a check. If
roundOff is greater than or equal to 50, round up and vice-versa with less than 50.
this is kinda confusing. is their a way that i can use the ceil() function to round the number.
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#include <iostream>
using namespace std;
int main()
{
int cinValue;
cout << "Please enter a value: " << endl;
cin >> cinValue;
int finalVar = ((cinValue % 100) < 50) ? cinValue - (cinValue % 100) : cinValue + (100 - (cinValue % 100));
cout << "Rounded to the nearest hundredth: " << finalVar << endl;
return 0;
}
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I figured out the problem i was having and it is because the number i am using to round is a double.
Why are you using a double? Everything we can see here is int.
Becuase the number can have decimals and i use the same value to also find a percent and i didnt realize that % only works for int.
So did you solve your problem?
If you are having trouble with rounding a double, post your code here so that we can help.
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#include <iostream>
#include <string>
#include <algorithm>
#include <ctime>
using namespace std;
int main() {
bool game = true;
do {
char choice[25];
double budget_given, amount_spent, percent,rounding,final_round;
double new_budget, round2,round;
char dollar;
cout << " Would you like to use the budget calculator (y/n)?" << endl;
cin >> choice;
if (choice[0] == 'y') {
cout << "Enter the budget that you were allowed last year." << endl;
cin.ignore();
if (cin.peek() == '$') {
cin >> dollar >> budget_given;
}
else {
cin >> budget_given;
}
cin.ignore();
cout << " How much money did you spend last year?" << endl;
if (cin.peek() == '$') {
cin >> dollar >> amount_spent;
}
else {
cin >> amount_spent;
}
percent = (amount_spent / budget_given) * 100;
round = amount_spent % 100;
round2= amount_spent -round;
new_budget = amount_spent + 100;
cout << " You used " << percent << " % " << "of the previous budget" << endl;
cout << "Your next budget will be " << new_budget <<"$"<< endl;
}
else if (choice[0] == 'n') {
cout << " Have a nice day" << endl;
game = false;
}
} while (game != false);
system("pause");
return 0;
}
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I want to round amount_spent to the nearest hundred.
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#include <iostream>
#include <string>
#include <algorithm>
#include <ctime>
using namespace std;
double roundNearestHundredth(double d)
{
int d_i = d;
return ((d_i % 100) < 50) ? d_i - (d_i % 100) : d_i + (100 - (d_i % 100));
}
int main()
{
bool game = true;
do
{
char choice[25];
double budget_given, amount_spent, percent;
double new_budget;
char dollar;
cout << " Would you like to use the budget calculator (y/n) : ";
cin >> choice;
if (choice[0] == 'y')
{
cout << "Enter the budget that you were allowed last year : ";
cin.ignore();
if (cin.peek() == '$')
{
cin >> dollar >> budget_given;
}
else
{
cin >> budget_given;
}
cin.ignore();
cout << " How much money did you spend last year? : ";
if (cin.peek() == '$')
{
cin >> dollar >> amount_spent;
}
else
{
cin >> amount_spent;
}
percent = (amount_spent / budget_given) * 100;
new_budget = roundNearestHundredth(amount_spent);
cout << " You used " << percent << " % " << "of the previous budget" << endl;
cout << "Your next budget will be " << new_budget <<"$"<< endl;
}
else if (choice[0] == 'n')
{
cout << " Have a nice day" << endl;
game = false;
}
}
while (game != false);
system("pause");
return 0;
}
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