Loan Program Code
Why is my code for more than 6 inputs when I only have 6 inputs set?
I'm only allowed to change lines 34-57, the rest was given.
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#include <iostream>
#include <string>
using namespace std;
bool promptYN(string msg)
{
char entered;
cout << msg << endl; // in front
cin >> entered;
return entered == 'y' || entered == 'Y';
}
int promptInt(string msg)
{
int number;
cout << msg << endl; // in front
cin >> number;
return number;
}
int main()
{
bool homeowner, employed;
int age, income, assets, creditScore, money;
// Do not rearrange this prompt order.
age = promptInt("Age: ");
income = promptInt("Income: ");
assets = promptInt("Assets: ");
creditScore = promptInt("Credit Score: ");
homeowner = promptYN("Home Owner [yn]: ");
employed = promptYN("Employed [yn]: ");
// BEGINNING OF YOUR CODE
money = 0;
cin >> age >> income >> assets >> creditScore >> homeowner >> employed;
if ((age >= 18 && creditScore >= 650 && income >= 20000) || (age >= 18 && creditScore >= 650 && assets >= 30000))
if (creditScore >= 650 && creditScore <= 699)
money += 10000;
else if (creditScore >= 700 && creditScore <= 749)
money += 20000;
else if (creditScore >= 750 && creditScore <= 799)
money += 30000;
else if (creditScore >= 800)
money += 40000;
if (homeowner == 'y' || assets >= 50000)
{
money += 10000;
cout << "Qualified for $" << money;
}
else if (homeowner == 'y' && assets >= 50000 && age >= 40)
{
money += 15000;
cout << "Qualified for $" << money;
}
else
cout << "Disqualified for loan";
// END OF YOUR CODE
return 0;
}
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Last edited on
Nevermind, I figured it out, haha. It's a bit silly but it did it by default. I didn't need a cin.
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