odd num, is this right?

[yp9h0pDG]

#include <iostream>
using namespace std;


int main() {
int n, x, m, div, pow=1, i=0;

cin>> n;
x=n;
do{
x/=10;
pow*=10;
}while(x>=10);


div=pow;
do{
m=n/div%10;
div/=10;


if(m%2==1){
i++;

cout<<m;

}
}while(div>=1);
if(i==0){

cout<<"0";

}

[dhayden]

It's easier to form the result as a number instead of printing it out one digit at a time:

#include <iostream>
using namespace std;

int
main()
{
    int n, digit, result=0, pow = 1;

    cin >> n;

    while (n) {
        digit = n % 10;
        n /= 10;
        if (digit % 2) {
            result += digit * pow;
            pow *= 10;
        }
    }
    cout << result << '\n';
}

[Duthomhas]

Another option is to simply count the number of times you have output a digit (or simply if you have using a boolean), and output a zero if you have not.

[SamuelAdams]

Can someone tell me what this means ?

x/=10;

[Duthomhas]

x = x / 10;