how to encrypted ID of last 4 digit
need to be able to write a code that read the number bit by bit
& also the first digit has to be * 4 and then the second digit * 3 then so on last digit by *1
also the rule is that the int cant be zero if its zero make the digit to 9 if higher then 9 add the to digit together
exp:4 * 4 = 16 1 + 6 = 7 so the new digit is 7
Here's image link:
http://i48.tinypic.com/2hrl4de.png
& also the first digit has to be * 4 and then the second digit * 3 then so on last digit by *1
also the rule is that the int cant be zero if its zero make the digit to 9 if higher then 9 add the to digit together
exp:4 * 4 = 16 1 + 6 = 7 so the new digit is 7
Here's image link:
http://i48.tinypic.com/2hrl4de.png
Last edited on
That shouldn't even compile. You need to go over the basics of programming in C++ again and re-write that.
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