Erasing elements from two vectors at the same position

[BMW330i]

Im trying to make a program that erases the zeros in a vector but i get the error:

/Users/T_HEN1203/Documents/Stats.cpp|62|error: no matching member function for call to 'erase'

The reference i read said i could use a position to but that doesnt seem to be working

int main() {
        std::vector<float> calc1 = {7, 5, 16, 8};
        std::vector<float> calc2= {4, 5, 0, 8};
       
        for (unsigned int x(0); x < calc1.size(); ++x) {
            if (calc1.at(x) == 0 || calc2.at(x) == 0){
                calc1.erase(calc1.at(x));
               
                calc2.erase(calc2[x]);
            }
        }
    }
    else{
        std::cerr<<"ERROR: The file isnt open.\n";
    }
    return 0;
}

Thanks to MrHutch i figured out how to remove the zeros but how would i remove the number from vector<float> calc2 that's at the same spot as vector<float> clac1?
I left the code above unchanged to help visualize what i'm talking about.

[MrHutch]

That's because the erase method(s) works with iterators. You're passing a float.

If you want to erase all of the zero values in a vector, you could use erase combined with std::remove_if and a predicate.

Working example: https://ideone.com/lyetdE