Creating an array of functions?

[Ed Sheeran]

I basically wanna create an array with functions for example I have:

  void draw0(){};
  void draw1(){};
  void draw2(){};

and I tried doing:

typedef void(*fn)();
fn func[3] = {draw0, draw1, draw2};

but when I try to output it

 cout << func[0] << endl;

it outputs the hex value. Any suggestions?

[CortezBen]

Line 2: error: 'draw0' undeclared here (not in a function)
Line 2: error: 'draw1' undeclared here (not in a function)
Line 2: error: 'draw2' undeclared here (not in a function)

[Ed Sheeran]

I have code in all of the functions this way just to show what I'm trying to do

[Naughty Albatross]

Hi,

You didn't call the function. You may try :
cout << (func[0])() << endl;

Edit : If you don't call it, std::cout only prints the address of a function alone. If you decide to call the function, you should specify a return value for your draw functions or otherwise it won't work. std::cout cannot output void return value after all

Hope that helps.

[Ed Sheeran]

Trying
cout << (func[0])() << endl;
won't compile and assigning the function in main still returns hex value and doesn't execute the function.

[Naughty Albatross]

Could you please show us the error(s) from your complier?

[Ed Sheeran]

I changed the functions to int and it works but how do I get rid of return that is also printed?

[Naughty Albatross]

> I changed the functions to int and it works but how do I get rid of return that is also printed?

What do you mean by that? You do not want cout to print the return values from your draw functions?

[Ed Sheeran]

Yeah, that's why they were void first but since I can't call them without a return value I changed to int

[Naughty Albatross]

> Yeah, that's why they were void first but since I can't call them without a return value I changed to int

You can simply call a function anywhere (inside or outside a cout command). Calling a func inside cout requires a return value other than void though, but I think it is safe to just remove the cout part and just call the function for good.

[Ed Sheeran]

It's working now, thanks a lot. I'm making a game and I wanna add a new "frame" of a picture after every input and switching through functions seemed the easiest to do.

[Naughty Albatross]

Good to hear :)