Basic Repetition finding max and minimum

[Newbcoder]

Hello everyone, I gots a question. This is how I wrote it, the run and compiler works fine but here's the problem. Note this is homework.

1. The last two numbers I input are the answer to this code equation.
2. All numbers must be identified giving out only two answers besides the last two.

What must be used :

1. Repetition such as For and While.
2. This is just C++

#include <iostream>
#include <ctime>
#include <cstdlib>


	int times, s=0, l=0, val;
	cout << "How many numbers do you want to input?" << endl;
	cin >> times;
	
	for(int i = 0; i < times; i++)
	{
		cout << "Enter a number " << endl;
		cin >> val;
	if (val < rand()% 100 + 1)  // This is my range from 1 to 99.
	{
   		l = val; // L means largest
   	}
   	else
	   {
   		s = val; // S means smallest
	   }
	}
	
	cout << "The largest number was " << l << endl;
	cout << "The smallest number was " << s << endl;
	return 0;
}

Do you guys see my problem?

[Abhi589]

Your program isn't written right.
Main thing is it doesn't have main function at all! If you are using ctime, you should use the line srand(time(0)) for really, but I don't get why you need to use the rand function


If you only want to find the largest and smallest, you could do this:

#include <iostream>
using namespace std;

int main()
{

	int times, s, l=0, val;
	cout << "How many numbers do you want to input?" << endl;
	cin >> times;

	for(int i = 0; i < times; i++)
	{
		cout << "Enter a number " << endl;
		cin >> val;
		if (val>l)
            l = val;
        if (val<s)
            s = val;
	}

	cout << "The largest number was " << l << endl;
	cout << "The smallest number was " << s << endl;
	return 0;
}