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why does this program terminate?

crepe6 (14)
i'm not sure why this function terminates after selecting an option? example 'e' to encipher. I want t be able to enter text. It works without the if statement.

thank you.

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#include <iostream>
#include <algorithm>
#include <string>
#include <sstream>
#include <cstdlib>
#include <cmath>
#include <ctime>
#include <vector>

using namespace std;

const string ALPHABET = "ABCDEFGHIJKLMNOPQRSTUVWXYZ.,' ";


string create_permutation(unsigned seed)
{
srand(seed);
string permutation = ALPHABET;
// using built-in random generator:
random_shuffle(permutation.begin(), permutation.end());
return permutation;
}
void fixed_Rotor()
{

    char ALICE[30];
    char BOB[30];
    char option;
    int seed  = 0;
    string permu = create_permutation(seed);
    string p;

    cout << "Enter seed to generate permutation: ";
    cin >> seed;

    cout << "encipher 'e' / decipher 'd' / quite 'q' ";
    cin >> option;

    if(option == 'e')
    {

        cout << "enter message to encipher" << endl;
        getline(cin,p);

        for(int i=0; i<p.size();i++)
        {
            for(int j=0; j<ALPHABET.size();j++)
        {
                if(p[i] == permu[j])
                {
                //cout << permu[i];
                    ALICE[i] = permu[i];
                }
            }
        }

         cout <<"ENCIPHERED TEXT: " << ALICE << endl;

    }
}
int main()
{
   fixed_Rotor();
}
Last edited on
Uk Marine (432)
Line 45, what is p.size()?
crepe6 (14)
the size of string p
MultiMedia (84)
Are you seeding your random num generator based on time?
crepe6 (14)
would it not be 0 because there is no input?
Uk Marine (432)
Where's your main() function?

EDIT: Sorry about my previous post, I didn't notice that in line 43 the string 'p' was getting input.
Last edited on
crepe6 (14)
I think so.

I was wondering why entering the if statement doesn't allow me to enter text using a string.

it works if i use char but i want to be able to use spaces.

char p;
cout << "enter message to encipher" << endl;
cin >> p;

EDIT: forgot to add the main.

Sorry I meant that a cin input works, not with the for loop because of the p.size(); but doesn't terminate the program.
Last edited on
Uk Marine (432)
You have to clear the cin buffer if you're working with getline
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cout << "encipher 'e' / decipher 'd' / quite 'q' ";
cin >> option;
cin.ignore();
crepe6 (14)
yeah I think that worked. thanks.
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