while and dividing

[materialisticsociety]

Hi. How do i make this program count the sum of the numbers that make up the enered number? e.g. '14' will be '5'. What should i put in the brackets? Idont know how to make this program know of how many numbers inputed number is made

 #include<iostream>

using namespace std;

int main(){

int n, sum=0;
cin>>n;
while(n/){



}


  return 0;
}

[Moschops]

#include <iostream>
#include <numeric>
#include <string>

using namespace std;

int main()
{
  string input;
  cin >> input;

  int product = std::accumulate(input.begin(), input.end(), 0,
				[](char a, int b)
				{
				  return b + (a-'0');
				}); 
  cout << '\n' << product << '\n';
}

[materialisticsociety]

thank, but how do i make it using while loop? im asking this because tomorrow ill have a test with while loop so im now "trainng" for it. im a total beginner knowing only for and while loops, havent worked with strings or any other fancy stuff yet

[Moschops]

This isn't any kind of "training in how to use the while loop". The while loop is simple.

while ( some_condition )
{

  //code

  // code that might set some_condition to false
}

That's everything there is to know about a while loop.

This is about algorithms. It requires the knowledge that an int divided by an int gives an int (e.g 123 / 10 = 12)

#include <iostream>
using namespace std;

int main()
{
  int value = 0;
  cin >> value;
  int sum = 0;
  if (value < 0) value*=-1;
  while(value > 9)
    {
      sum += value - ((value/10) * 10);
      value =value/10;
     }
  sum += value;
  cout << '\n' << sum << '\n';
}