Quinary to pentadecimal

[ralf102]

I've made a program that converts quinary number to pentadecimal. It works fine with most numbers, but with some, like 1143 it returns correct anwser with 0 at the beggining (1143 should be B8, but program returns 0B8). Can you help me with finding mistake in my code? I'd be grateful.

  #include <iostream>
using namespace std;
int main () {
int b,p,o,i,l,z,x,y;
int a;
cin >>a;
if (a<5)
    cout <<a;
b=a;
y=a;
i=0;
while (b>0){
    b=b/10;
    i++;
    }
o=1;
p=0;
l=i;
while (i>=0){
    p=a%10*o+p;
    a=a/10;
    o=o*5;
    i--;
}

x=p;
int t[l-2];
for (z=0;z<=l-2;z++){
    x=p%15;
    p=p/15;
    t[z]=x;
}
for (z=l-2;z>=0;z--){
    if (t[z]==10)
        cout <<"A";
    else if (t[z]==11)
        cout <<"B";
    else if (t[z]==12)
        cout <<"C";
    else if (t[z]==13)
        cout <<"D";
    else if (t[z]==14)
        cout <<"E";
    else
        cout <<t[z];
}
}

[Duthomhas]

You are unlikely to find anyone who wants to wade through that.

Remember that number base (or radix) is a polynomial to make life easier for humans.

All base conversions work like this:

  string s = <source number>
  int n = convert_from( base_a, s );
  string r = convert_to( base_b, n );

Hence, you'll need two functions: one to convert from (a base-5) string to an integer, and one to convert from an integer to a (base-15) string.

Hint: you only need a total of three variables maximum per function.