if statement where array contains string

[jsmootshaw]

Write your question here.
Does anyone know how to check if a string array contains a string?
can i use an if ststement.
Thanks.
#include <iostream>
#include <string>
using namespace std;
int main()
{
string order[10];

double total = 0.00;

for(int purchases = 0; purchases <= 1; purchases++)
{
cout << "Latte\t$2.50\n" << "Decaf\t$1.00\n" << "Mocha\t$3.00\n"
<< "Expresso$3.00\n";
cout << "What would you like to order?\n";
cin >> order[purchases];
}
for(int h = 0; h <= 1; h++)
{
if(latee == order[h]);
{
total = total + 2.50;
cout << "it works\n";
}
}
for(int i = 1; i <= 2; i++)
{
cout << order[i] << endl;
}
cout << "Your total is $" << total << endl;

return 0;

[integralfx]

edit: Oops, I misinterpreted the question.

http://www.cplusplus.com/reference/algorithm/find/

std::string haystack[5] = { /* . . . */ };
std::string needle{ /* . . . */ };
if( std::find( std::begin(haystack), std::end(haystack), needle ) != std::string::npos ) {
	/*
	. . .
	*/
}

[xismn]

The most rudimentary way of doing this:

#include <iostream>
#include <string>

int main() {

	constexpr int num_strings = 2;
	std::string strings[num_strings] = { "hello", "world" };
	//This is our array of strings.
	//It has two strings.

	std::string find_string = "world";
	//This is the string we're looking for.

	bool found = false;

	for (int i = 0; i < num_strings; ++i) {

		if (strings[i] == find_string) {
			found = true;
		}

	}

	if (found) {
		std::cout << "The string was found!" << std::endl;
	}
	else {
		std::cout << "The string wasn't found!" << std::endl;
	}

	return 0;
}

Note, that the for-loop doesn't terminate just because it's found the string we're looking for. All it does once our desired string is found is set found to true. If there were more string elements in our array, the for loop would continue searching the array, comparing elements against our find_string even though it was already found.