find

[i8bjz8AR]

int* find(int* first, int* limit, int value);

Returns: Returns a pointer to the first object in [first, limit) whose value is equal to value. Returns limit if no such object is found.

I'm not really sure what to do.. This is what I have.

#include <iostream>

using namespace std;

int* find(int* first, int* limit, int value){
  if()
    
    *value = (first * limit);
    std::cout << value << std::endl;

  }
}



void print(int* first, int* limit){
  while (first != limit){
    std::cout << *first << ' ';
    ++first;
  }
}

int main(){

  int a[] = {1, 2, 3,4,5};
  int* first = a;      // Points to the first object in a
  int* limit = a + 5;
  print(a, a + 5);

}

[Zhuge]

You'll want to do something similar to print(); iterate over the range provided, but instead of printing the values out increment a counter and return that if you find what you are looking for.