Calling by Reference and value

Mar 28, 2016 at 12:26am
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#include <iostream>
using namespace std;

bool figureGrade(int score, char &);

int main()
{
	int score;
	char grade;
	cout << "Please enter a score" << endl;
	cin >> score;
	cout << "The score you entered is " << score << endl;
	bool figureGrade(int score, char &);
	if (figureGrade(score, grade))
	{
		cout << "The student's grade is" << grade << endl;
	}
	return 0;
}

bool figureGrade(int score, char &)
{
	char character;
	if (score > 0 && score <= 100)
	{
		if (score > 90 && score <= 100)
			character = 'A';
		return true;
		if (score > 80 && score <= 89)
			character = 'B';
			return true;
			if (score > 70 && score <= 79)
				character = 'C';
				return true;
				if (score > 60 && score <= 69)
					character = 'D';
		return true;
		if (score <= 59)
			character = 'F';
		return true;
	}
	else
	{
		cout << "Invalid score. No grade given" << endl;
		return false;
	}
}





I was wanting to see if I could get a little help with this program. I feel like I am really close to having this program complete, but for some reason I can't seem to call the letter grade back from the function at the bottom. If I put a invalid score in, it will return my cout at the bottom of the function, but when I try to return the letter grades, all it gives me is an odd symbol. Any help would be appreciated. Thank you.
Mar 28, 2016 at 12:44am
Line 13
You've already declared your function prototype at Line 4, so no need to declare it again.

Line 21
It would be helpful to give your char& parameter a name, like so:
bool figureGrade(int score, char& grade)
Then instead of using the variable character, you can just use the parameter grade.

Also have a read on the tutorial on functions.
http://www.cplusplus.com/doc/tutorial/functions/
Mar 28, 2016 at 1:00am
Thank you very much. I see now why it wasn't working before. I need to cover functions again, thats probably my worst thing right now. Thank you!
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