Guessing game code

[scottishbear]

How's my coding? I am trying to build a guessing game that's between 1-20 in 3 guesses or less.


#include <stdio.h>
#include <time.h>

int main(void)
{
int Guesses = 5;
int Guess;
int Answer;

srand(time(NULL));
Answer = rand() % 20 + 1;

cout << " Welcome to the Guessing Game! \n";
cout << "I'm thinking of a certain number between 1 and 20, what is it?" << Guesses << "tries?\n";

for (int i = 0; i < Guesses; i++)
{
cout << "Guess #" << i+1 << ": ";
cin >> Guess;

if (Guess != Answer)
{
if(Guess > Answer)
cout << "to high.\n";
else
cout << "to low.\n";
}
else
{
cout << "you won!\n";
system("pause");
return 0;
}
}

cout << "you lost!\n";
cout << "The correct answer was :" << Answer << endl;
system("pause");
return 0;
}

[Chervil]

These headers tell me the code is written in the C language:

#include <stdio.h>
#include <time.h> 

but the use of cin and cout indicates it must be C++. So replace those two lines with the C++ headers:

#include <iostream>
#include <cstdlib>
#include <ctime> 

You also need to specify the namespace, by putting the prefix std:: where required, such as
std::cout and std::cin or for now just add

using namespace std;

at the top of the program, after the headers.

[Too Explosive]

It is common practice not to include void between the parentheses of int main. Just leave it empty.
int main()

And when you say to high or to low. I believe it should be "too"

To me it doesn't seem that the statements

cout << "you lost!\n";
cout << "The correct answer was:" << Answer << endl;

is nested in anything. Meaning it will always output these statements no matter what.

Those same statements could be made into one cout statement cout << "you lost!\nThe correct answer was :" << Answer << endl;(This also goes for lines 13 and 14)