Invalid conversion from int (*) to int. How to fix?

[Harutyun]

Hi, I'm trying to write a code that finds all the perfect numbers within the given range and store it in an array, and then std::cout it. Here is my code:

  #include <iostream>


int ifReturnPerfectOrZero(int iX)
{
    int iSum = 0;
    for (int iChecker = 1; iChecker < iX ; ++iChecker)
    {
        if (iX%iChecker == 0)
        {
            iSum = iSum + iChecker;
        }

        if (iX == iSum)
        {
            return iX;
        }
    }

    return 0;
}

int main()
{
    std::cout << "Enter limit (from zero to)" << std::endl;
    int iLim = 0;
    int Passer = 0;
    std::cin >> iLim;
    int iaPerfectNums[50];

    for (int iX = 1; iX < iLim; ++iX)
    {
        Passer = ifReturnPerfectOrZero[iX];
        iaPerfectNums[(iX-1)] = Passer;
    }
    
    std::cout << "The perfect numbers in the given range are:"
    
    
    for (int iNum = 0; iNum < iLim; ++ iNum)
    {
        if(iaPerfectNums[iNum] != 0)
        {
            std::cout << iaPerfectNums[iNums] << std::endl;
        }
    }

}

I'm using code blocks IDE 13.12


P.S. the error is on line 33, the array part does not work for some reason (invalid conversion from int (*) to int)

[Thomas1965]

To call a function you need the round brackets.
Passer = ifReturnPerfectOrZero(iX);