Not using repeating numbers

[KTlady]

So I'm creating a code that requires the user to enter a password it has to be 6 digits and not have preceding zeros, the numbers have to be unique as well. I have the first two things down in my code, I need help with making sure that the user cannot repeat numbers.

 #include <iostream>
#include <fstream>
#include <cmath>
#include <string>

using namespace std;

int main()
{
int num=0;

cout << "Enter six digit code." << endl;
cin >> num;


while (num>999999 || num<100000){

      cout <<"code doesn't have six digits." << endl;
      cout <<"Enter six digit code." ;
      cin >> num;
}
cout << num << endl;

//Exit program
return 0;

}.

[jlb]

Have you considered using string to hold the "numbers"? It is much easier to insure a string has a certain length than it is with a number. Also you can then check that each digit is unique.

[KTlady]

No, I haven't. I am a little confused at what you mean.

[jlb]

I am a little confused at what you mean.

What exactly are you confused about?

Remember that not all "numbers" are really numbers.

[xismn]

@KTlady
Do you know what strings are? I assume you do since you're including <string>.

[Duthomhas]

1. Read the code as a string (not a number).
2. Check that the first character is not '0'.
3. Sort it.
4. Look through it to see if there are any identical character values adjacent to each other.

Hope this helps.