help with this..i confuse

MY COMMAND(WHERE THE FIRST VALUE IS 25,25,12):
#include "stdafx.h"
#include<iostream>
using namespace std;

void main()
{int Data_1,Data_2,Data_3;
cout<<"key in first number:";
cin>>Data_1;
cout<<"key in second number:";
cin>>Data_2;
cout<<"key in third number:";
cin>>Data_3;
if((Data_1>Data_2)&&(Data_1>Data_3))
{
cout<<Data_1<<": is the biggest\n";
}
else if((Data_2>Data_1)&&(Data_2>Data_3))
{
cout<<Data_2<<": is the biggest\n";
}
else
{
cout<<Data_3<<": is the biggest\n";
}
}

MY OUTPUT:
key in first number:25
key in second number:25
key in third number:12
12: is the biggest
Press any key to continue . . .

WHY I GET 12 INSTEAD OF 25?????????????????

Last edited on

Moooce (216)

Try to see the numbers in your code instead of the variables and you'll see why you get the result you do..

1
2
3

if( 25 > 25 && 25 > 12 ) false
else if( 25 > 25 && 25 > 12 ) false
else cout << Data_3 which is 12

cire (8284)

WHY I GET 12 INSTEAD OF 25?????????????????

Because your logic is wrong.

if ((Data_1 > Data_2) && (Data_1 > Data_3))

Let's consider what that looks like when the variables have the values you entered:

if ((25 > 25) && (25 > 12))

25 > 25 is false, so the if statement evaluates to false. Therefore, the statement governed by the first if statement will not execute. Data_1 is not the biggest.

else if((Data_2>Data_1)&&(Data_2>Data_3))
turns into:
else if((25 > 25) && (25 > 12))

25 > 25 is false, so the if statement evaluates to false. Data_2 is not the biggest.
There's only one option left, and that's 12.

shaven (5)

Thanks..I not notice it..

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help with this..i confuse