lambda expression problem

#include <vector>

int main(){

    std::vector<double> vec(100);
    //...initialize it

    double sum= [&vec]{       
	double sum{ 0 }; 
	for (auto x : vec)
	    sum += x;
	return sum;
    };

}

I'm getting compiler error

no suitable conversion function from "lambda []double()->double" to "double" exists

I dont really understand this conversion problem. Even this isnt working and is giving me the same error
double random_number = []{ return double{ 2 }; };

What exactly am I missing? Any help appreciated!

Last edited on

Cubbi (4774)

"[]{ return double{ 2 }; }" is a function object, you can't store that into a variable of type double.

If you want to call the function, you need to use the function call operator():

double random_number = []{ return 2.0; }();

etrusks (398)

Tnx a lot for answer man!

Its weird that () is after body not before it.

Both codes actually work even if i dont change them just put () after lambdas body.

When I read Stroustrups book he said that i dont even have to use parentheses if lambda doesnt take any arguments so the shortest lambda would be []{}, now turns out its []{}()?

Cubbi (4774)

the function call operator () always appears after the function: rand(), getchar(), []{ return 2.0; }()

[]{} is the shortest lambda expression.
If executed, it results in a nameless function that may be stored in a varable or called right away:

1
2
3

auto f = []{}; // create and store
f(); // call the stored lambda
[]{}(); //  create and call right away

Last edited on

etrusks (398)

Ohh, thank you very much man, very appreciated :)

Topic archived. No new replies allowed.

C++

Forum

lambda expression problem