The (Almost) Infinite Loop, for (){}...
In the following example, why does the code execute 200 times if I enter 1000? Shouldn't the for loop die, when I enter 1000 (1000>x), or does it view all variables (excluding the one included in the actual condition), before "for(){}" as constant? this is so confusing. Does "while" behave the same way, setting all prior variable as constant? I don't think so because I've tested it before.
bla bla bla...
int main()
{
int x, y;
y=200;
for (int x; x<y; x++)
{
cin>>y; cout<<"hell yea\n";
}
return 0;
}
bla bla bla...
int main()
{
int x, y;
y=200;
for (int x; x<y; x++)
{
cin>>y; cout<<"hell yea\n";
}
return 0;
}
Last edited on
You haven't set x (either one of the two) to any value. Why would you think it was less than the number you enter for y?
You didn't initialize
My compiler actually doesn't let me compile this because you are using an uninitialized variable before you assign a value to it. Your program's behavior is considered to be 'undefined'.
x anywhere. There's no way of knowing what that value is.My compiler actually doesn't let me compile this because you are using an uninitialized variable before you assign a value to it. Your program's behavior is considered to be 'undefined'.
Yea, you're right, it works fine now. I must have messed something up in the code the other day. I was trying to emulate something, which I did then. It's so easy to make mistakes with this stuff... next time i'll post the code, after I make it.
Sorry about that guys.
Sorry about that guys.
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