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How do I go about reversing the numbers in an array to what they where imputed

willmannix1 (12)
I am a bit stuck on how to approach reversing the order of an array so that for example i enter the numbers
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2
3
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5

into the array and they are outputted like
5
4
3
2
1

I am doing a menu where each option displays a certain task carried out on the array i.e option 1 displays the smallest number option 2 displays the average of the numbers in the array etc...
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  #include "stdafx.h"
using namespace std;

int main()
{
    
	int big, small, value, count = 0;
	int list[12];
	int option;
	int sum = 0;
	big = small = list[0];

	cout << "Enter 12 numbers : ";
	for (int i = 0; i < 12; i++)
	{

		cin >> list[i];

	}

	do
	{

		cout << "\t\tMenu\n";
		cout << "\t0.Display\n";
		cout << "\t1.Total\n";
		cout << "\t2.Average\n";
		cout << "\t3.Largest\n";
		cout << "\t4.Smallest\n";
		cout << "\t5.Occurance of value\n";
		cout << "\t6.Multiply values by number entred\n";
		cout << "\t7.Reverse array\n";
		cout << "\t99.Exit\n";
		cout << "\t\t Option ? ";
		cin >> option;


		switch (option)
		{
		case 0:

			cout << "Contents\n";


			for (int i = 0; i < 12; i++)
			{
				cout << list[i] << endl;

			}
			break;

		case 1:

			cout << "Total";
			cout << "\n\n";

			for (int i = 0; i < 12; i++)
			{


				sum += list[i];

			}

			cout << sum;

			break;

		case 2:

			cout << "average";

			for (int i = 0; i < 12; i++)
			{
				sum += list[i];

			}

			cout << setprecision(1) << fixed << sum / 12;

			break;

		case 3:

			cout << "Largest";

			for (int i = 0; i < 12; i++)
			{
				if (list[i] > big)
				{
					big = list[i];
				}

			}

			cout << big;

			break;

		case 4:

			cout << "Smallest";

			for (int i = 0; i < 12; i++)
			{
				if (list[i] < small)
				{
					small = list[i];
				}

			}

			cout << small;

			break;

		case 5:

			cout << "Occurances of value";

			for (int i = 0; i < 12; i++)
			{
				
				cout << "Enter value to search for: ";
				cin >> value;
				for (int i = 0; i<12; i++)
					if (list[i] == value)
						count++;
				cout << value << " occurs " << count << " times" << endl;

			}

			break;
		case 6:
			cout << "Enter value that you wish to multiply the contents \n in the array by : ";
			cin >> value;

			for (int i = 0; i < 12; i++)
			{
				
				list[i] = value * list[i];
			
				cout << list[i] << endl;
			}
		
			break;
case 7:

			break;


		case 99:
			break;

		default:
			cout << "Invalid option\n";
		}

		} while (option != 99);
	
	
	return 0;


case 7 is the one im stuck on, not sure how to approach it, any help will be appreciated :)
Last edited on
closed account (E0p9LyTq)
You already have a case for listing the contents of the array, just change that case code to do a reverse loop through the array:

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case 7:
   cout << "Reverse contents:\n";

   for (int i = 11; i >= 0; i--)
   {
      cout << list[i] << endl;
   }
   break;
willmannix1 (12)
ahh i see, cheers for that mate :)
closed account (E0p9LyTq)
BTW, your variable declarations is a bug lurking to strike:

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int big, small, value, count = 0;
int list[12];
int option;
int sum = 0;
big = small = list[0];


You are assigning an uninitialized variable to two other uninitialized variables. I'd change it to something like this:

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int big = 0;
int small = 0;
int value = 0;
int count = 0;
int list[12] = { 0 };
int option = 0;
int sum = 0;


list's initializer list assigns 0 to all 12 of list's elements.
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