How do we seperate digits by adding space between them?

[kamilhassaan]

If I type a number, the computer should display the number by giving space between between them.

For example; if I type 56, the computer should print out 5 6. Similarly if I type 5681, the computer should print out 5 6 8 1. Also, if i type -2345, the computer should print out 2 3 4 5.

I don't even know how to start making this

[2UD8vCM9]

#include<iostream> //include iostream for input and output
#include <string> //include string for the string object

using namespace std; //using namespace std for string and cout

int main()
{
	string userinput; //stores the numbe that the user enters
	cout << "Please enter a number: ";
	getline(cin, userinput); //Place the user's # that they typed into the string userinput
	int numberlength = userinput.size(); //number length holds the # of digits of the user input
	for (int i = 0; i < numberlength; i++) //for each digit in the user input
	{
		if (userinput[i] >= '0' && userinput[i] <= '9') //if digit is 0-9
		{
			cout << userinput[i] << " "; //Print out digit with a space after the digit
		}
	}

	return 0;
}

[Arslan7041]

Im assuming arrays are not allowed for the assignment, so the above solution is probably not helping at all...

[kamilhassaan]

My friend I appreciate your help but I forgot to mention that I just started C++. I do not know what "string" is.
This is all I know

#include <iostream>
using namespace std;
int main()
{
	int num=0,...;
        
	return 0;
}

We haven't started arrays yet.

I only know;
If-Else
If
While Loops
For Loops
Do While Loops

[2UD8vCM9]

No problem kamilhassaan.

I have rewritten it to use the knowledge that you know.

#include<iostream> //include iostream for input and output

using namespace std; //using namespace std for string and cout

int main()
{
	char userinput; //stores the digit
	cin >> userinput; //get single character from user input
	while (userinput != '\0') //while not at null terminator from user pressing enter
	{
		if (userinput >= '0' && userinput <= '9') //if entered character is a digit
		{
			cout << userinput << " "; //print character with a space
		}
		cin >> userinput; //get next character to check if it is null terminator or another digit
	}
}

[TarikNeaj]

@Pindrought. We don't do peoples assignments here, which is exactly what you did. Next time, help him out with tips and such, and let him write his own code, this way he will learn nothing.

[andywestken]

Note that the termination condition on line 9 is incorrect.

By default, whitespace is ignored by the extraction operator, so the return key will be ignored.

The result of typing 1<return>2<return><return>3<return><return><return>... is:

1
12
2
3
3

4
4

using

#include <iostream>

using namespace std;

int main() {
    //cin >> noskipws;

    char ch = '\0';
    do {
        cin >> ch;
        if (ch == '\0')
            cout << "\\0";
        else if (ch == '\n')
            cout << "\\n";
        else
            cout << ch;
    } while (ch != '\0');

    return 0;
}

If you uncomment line 6 so whitespace is not ignored, you get

1
1\n2
2\n
\n3
3\n
\n
\n4
4\n
\n
\n
\n

So you can see the <return> key inserts an '\n' into the stream, not a '\0'

Andy

[andywestken]

I don't even know how to start making this

Without knowing the point of the exercise it's hard to suggest a particular solution.

If you've only been working with int variables and loops, etc, when there is another solution which works with int maths. As you haven't touched on arrays then it start off by working out the highest power of ten for the number (using a while loop.) Etc.

Andy

[D80DSL3A]

nvm

[Duthomhas]

These kinds of homeworks aren't interested in your ability to play with strings, so forget all that.

The idea is for you to be able to separate an integer value into digits. Do that with basic math: division and remainder. C++ provides two simple operators that do just that.

I don't know if you are expected to use recursion for this, but without arrays of any kind you must either:
1) use recursion
2) reverse the digits of the number before displaying them

Neither method is particularly easy to understand at first.