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Checking for a Char in Char Array;

Marth (58)
My brain has shut off, I know how to do this, i just cant seem to put it together.


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char seat;
letter = 'A';
char alphabet[26];
int seats_amt = 5; //this is actually a user defined var.
 
cin >> seat;
		
		if (islower(seat))
			seat = toupper(seat);
		

		for (int i = 0; i < seats_amt; i++) {
			alphabet[i] = i + letter;
		if (seat == alphabet[i]) 
			cout << "You entered " << alphabet[i] << endl;
		else
		{
			cout << "Re-enter Letter.\n>";
			cin >> seat;
		}
		}


the problem is that i need to check the input 'seat' against each iteration of the alphabet in the array. but alphabet[i] only works in the for loop bracket. But keeping it in the for loop spits out the ELSE bracket 5 (seats_amt) times.

i feel like its such a stupid and obvious thing that im missing here.
Kevin C (319)
There are many ways to solve this. Functions would be the best. Do you know how to use functions?
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