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Switch Statement Won't Run?

dvarona1 (6)
I've been working on this code for hours trying to find a reason why my switch statement won't run and I've run out of ideas. Anyone see what the issue might be?
The program question I'm trying to solve if needed is: A mobile phone service provider has three different subscription packages for its customers:

Package A: For $39.99 per month 450 minutes are provided. Additional minutes are $0.45 per minute.

Package B: For $59.99 per month 900 minutes are provided. Additional minutes are $0.40 per minute.

Package C: For $69.99 per month unlimited minutes are provided.

Write a program that calculates a customer’s monthly bill. It should ask which package the customer has purchased and how many minutes were used. It should then display the total amount due.

Input Validation: Be sure the user only selects package A, B, or C.

When I run the program, I'm able to select a Package and then it asks to type the minutes used, after that it just says "Press Any Key to Continue"

Thanks for any help.

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 #include <iostream> 
using namespace std;

int main()
{

	int time;
	double total = 0.0;
	// Store the package and rates in variables.
	double packageA = 39.99;
	double packageB = 59.99;
	double packageC = 69.99;
	double rateD = 0.45;
	double rateE = 0.40;
	char package;

	//Display the following choices for the user.
	cout << "Select a subscription package. " << endl;
	cout << "A. Package A" << endl;
	cout << "B. Package B" << endl;
	cout << "C. Package C" << endl;
	cin >> package;

	// Validation
	if (package < 'A' || package > 'C')
	{

		cout << "Package must be A, B, or C. ";
		return 1;
	}

	
	cout << "How many minutes were used? " << endl;
	cin >> time;

		switch (package)
		{
		case 'A':
		{
			if (time < 450)
				total = packageA;
			// If the time is less than required. Then no extra charge. 
			else
				total = ((time - 450)*rateD) + packageA;
			// If the time exceeds the requirements, then a extra charge is added.
			break;
		}
		case 'B':
		{
			if (time < 900)
				total = packageB;
			else
				total = ((time - 900)*rateE) + packageB;
			break;
		}
		case 'C':
		{
			total = packageC;
			break;
		}


		default: cout << "Total amount due is: $" << total << endl;
		}

	system("pause");
	return 0;
}
Last edited on
Norm Gunderson (112)
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		switch (package)
		{
		case 'A':
		{
			if (time < 450)
				total = packageA;
			// If the time is less than required. Then no extra charge. 
			else
				total = ((time - 450)*rateD) + packageA;
			// If the time exceeds the requirements, then a extra charge is added.
			break;
		}
		case 'B':
		{
			if (time < 900)
				total = packageB;
			else
				total = ((time - 900)*rateE) + packageB;
			break;
		}
		//case 'C':
		default:
		{
			total = packageC;
			break;
		}


		//default: cout << "Total amount due is: $" << total << endl;
		}

		cout << "Total amount due is: $" << total << endl;


Should fix it
dvarona1 (6)
Ahh yeah my professor did say something about Case C not going to be needed. Now I understand, Thanks so much!
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