Function parameters in an if statement

[DDomjosa]

Hi, is there a way to execute a line of code if the function is provided with 2 parameters and another line of code if it's provided with only 1 instead? Let's say I have this function:

int blah(const char* prompt, int y = 0)
{
    std::cout << prompt << std::endl;
    if (y is provided)
    {
        do something with y;
    }
    if (y is not provided)
    {
        do another thing in general;
    }
}

If in main() I call blah("The prompt", 5);, I want it to execute the if (y is provided) code, if I call blah("The prompt"); I want it to execute the if (y is not provided) code. What should be next to if? Thanks!

[LB]

This is what function overloading is for. Create two versions of the function: one with two required parameters and one with one required parameter. Default parameters are only useful when your code is the same in both cases.

[DDomjosa]

Thank you, that is what I was looking for. I'll go figure out how to use it properly now.