2D Arrays Help
Sep 25, 2015 at 2:57am UTC
For this 2D array, I was asked to search for a number. Once found I needed to output its location. Could someone explain to me how would I find the number's index location.
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#include <iostream>
using namespace std;
void fillArray(int a[][5], int size);
void printArray(int a[][5], int size);
int countNums(int ar[][5], int size, int search);
int main()
{
int ar[5][5];
fillArray(ar, 5);
printArray(ar, 5);
cout << "What number do you want to search for? " << endl;
int num;
cin >> num;
int count = countNums(ar, 5, num);
cout << "Your number appears " << count << " times in the array" << endl;
return 0;
}
void fillArray(int a[][5], int size)
{
for (int row = 0; row < 5; row++)
{
for (int col = 0; col < 5; col++)
{
a[row][col] = rand() % 10 + 1;
}
}
}
void printArray(int a[][5], int size)
{
for (int row = 0; row < 5; row++)
{
for (int col = 0; col < 5; col++)
{
cout << a[row][col] << "\t" ;
}
cout << endl;
}
}
int countNums(int ar[][5], int size, int search)
{
int count = 0;
for (int row = 0; row < 5; row++)
{
for (int col = 0; col < 5; col++)
{
if (ar[row][col] == search)
count++;
}
}
return count;
}
Sep 25, 2015 at 3:08am UTC
@besurk
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for (int row = 0; row < size; row++) // May as well use the variable sent to the function
{
for (int col = 0; col < size; col++)
{
if (ar[row][col] == search)
{
count++;
cout << search << " found at array location [" << row << "][" << col <<"]" << endl;
}
}
}
return count;
Last edited on Sep 25, 2015 at 3:10am UTC
Sep 25, 2015 at 3:21am UTC
Upon implementing this code, It outputted all locations for the 25 numbers in the array. Any ideas?
Sep 25, 2015 at 4:18am UTC
@besurk
Did you remember to add the parenthesis' around count++ and the cout statement?. If yes, then please post your countNums function
Sep 26, 2015 at 4:00pm UTC
Awh, yes. I was missing the braces in the if statement. Thank you
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