I've defined one function and am taking 2 values off it by calling it 2 times. Like this:
count1=counter(subject1);
couunt2=counter(subject2);
But the problem is that the process is being run only once.
But if I modify the code like this:
count1=counter(subject1);
cout << count1 << endl;
count2=counter(subject2);
Then the process is ok. This is also true for cout << ""; in the place of the previous cout.
I can't seem to understand what is really going on.
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#include <iostream.h>
int digits(long long);
int main()
{
long long num1, num2;
while(cin >> num1 >> num2)
{
int lnm1, lnm2;
lnm2=digits(num2);
cout << "";
lnm1=digits(num1);
}
return 0;
}
int digits(long long n)
{
int i, j, rem;
for (i=10, j=1 ; rem>=0 ; i*=10, j++)
{
rem=n-i;
cout << "rem for " << n << "=" << rem << endl;
}
return j-1;
}
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[b]EDIT::::::::[/B]
Later I did something this
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#include <iostream.h>
int digits(long long);
int main()
{
long long num1, num2;
while(cin >> num1 >> num2)
{
int lnm1;
lnm1=digits(num1);
//cout << lnm1 << endl;
int lnm2;
lnm2=digits(num2);
//cout << lnm2 << endl;
}
return 0;
}
int digits(long long n)
{
int i, j, rem;
for (i=10, j=1 ; rem>=0 ; i*=10, j++)
{
rem=n-i;
cout << "rem for " << n << "=" << rem << endl;
}
return j-1;
}
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This is now working correctly but my question is why can't it be like the first one?