Print a string in reverse order using cout

[cnj3]

I am stuck on one part of an assignment. Among other things, we have to get a character string of random length from a user and then reverse and output that string. In order to do this, I need to be able to call my string length function inside of my print backwards function, but I cannot figure out how to do it. I cannot change the function definitions.

  void GetStringLength(char * c, int * length)
{
  *length = 0;

  for (int i = 0; c[i] != '\0'; ++i)

  *length += 1;  
}

void PrintStringBackwards(char * const c)
{
  GetStringLength(c, &l);
  char swap;
  for (int j = 0, k = *length; j < *length; ++j, --k)
 {
	 swap = c[j];
	 c[j] = c[k];
	 c[k] = swap;
	 std::cout << c[j];
 }  
}

[funprogrammer]

char *c is a pointer to character. It gives you the current character at that particular location of memory. Every string in c++ is terminated by "\0"(null) character. Using char* you can read the characters till you reach "\0". Increment a counter during this process. When you reach the null character you should have the string length in the counter. Hope this helps

[cnj3]

Thank you for the response. I have the length of the string, but I cannot get it to reverse. Any ideas?

[CodeWriter]

You need perhaps to access each character in reverse order?
This code gets each character and prints it, does that give you any ideas?

#include <iostream>

using namespace std;

int main()
{
    string myString = "THIS IS A TEST STRING";
    for (unsigned int i=0;i<myString.length();i++)
    {
        cout << myString[i];
    }
    cout << endl;
    return 0;
}

[cnj3]

Yes! I got it! I was making it way too complicated. Thank you both so much for your replies and assistance.