name of function

[Filorn]

I copied this function from a C guide but i don't know why the function type is void and not int or another one.

void swap(int *a, int *b) {
int tmp;
// tmp conterrà il contenuto della variabile intera puntata da a
tmp=*a;
// a conterrà il contenuto della variabile intera puntata da b
*a=*b;
// b conterrà il contenuto della variabile intera puntata da tmp
*b=tmp;
}

[CodeWriter]

Because there is nothing for the subroutine to return.
You pass the address of the pointers to where the numbers are in memory.
You then swap the values in those memory locations.

#include <iostream>

using namespace std;

void swap(int *a, int *b) {
    int tmp;
    tmp=*a;
    *a=*b;
    *b=tmp;
}

int main()
{
    int x = 5;
    int y = 7;
    swap (&x,&y);
    cout << x << " " << y << endl;
    return 0;
}

[Filorn]

ok thanks i supposed that