Why is string with less characters greater than one with more?

[The Fearless Hyena]

I'm simply trying to figure out why a string with less characters is considered
to be greater than one with more characters. My assumption would be that s3 would be less than s2 since it isn't as long.

#include <iostream>
#include <string>

using std::cout;
using std::cin;
using std::endl;
using std::string;

int main()
{
	string s1("Hello");
	string s2("Hello World");
	string s3("Hiya");

	if(s3 > s2)
		cout << s3 << endl;

	return 0;
}

[Zhuge]

It is using lexographical ordering. Go letter by letter; the 'H' characters are equal, but 'e' < 'i' (you could think of it as 'e' comes before 'i' in the alphabet). This is also how words are ordered in a dictionary. If you want to factor in size, you'll need to compare those yourself.

[SamuelAdams]

What Zhuge said, if you print out the decimal value for e, you should get 101 but if you print the value for i you should get 105.

If you want to the longer strings to be greater then you'll need to use string size.

http://www.cplusplus.com/reference/string/string/size/

[The Fearless Hyena]

Ah, so it goes by the ascii table values.

Thanks guys.