i gets -

[agorski]

Alright I have done some coding before, and never an into a problem like this.
This is pretty simple code for an array, but I can't get it to not run an infananite loop. What am I doing wrong?

x = 10;
plays[x];
sum = 0;
for(i=0; i < x; i++){
plays[i] = i-x;
sum = abs(plays[i]) + sum;
printf("\nI: %d Plays: %d Sum: %lg\n", i, plays[i], sum);
}

[PeteBongo]

Is this your code?
like that it is never going to be compiled, because you did not declare all those variables.
if you did, check if "x" is const , an array may only have a const number of elements (at least if you declare it that way).
I suggest (not tested)

const unsigned int x = 10;
float plays[x];
float sum = 0;

for(unsigned int i=0; i < x; i++)
{
  plays[i] = i-x;
  sum = abs(plays[i]) + sum;
  printf("\nI: %i Plays: %f Sum: %f\n", i, plays[i], sum);
}

[agorski]

See I thought that was it too, but I ran it in both Visual studios and kwrite and got the same problem with both. The only difference I got was with x it could have been either 5 or 10 for kwrite. I can't figure out why this would do that. Also I am not in C99 for the project and can't declare like that I don't think.

[agorski]

Thank you Pete The unsigned was the part I missed, but why would I need that.

[PeteBongo]

It is because the compiler has to make sure that arrays do not have a negative amount of elements.

e.g.
int foo[-2]; //this is obviously nonsense