Alphabetical order
As you know problem is Alphabetical sorter but without vowel letter.
What do you suggest me?
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#include <string>
#include <iostream>
#include <algorithm>
#include <vector>
using namespace std;
void Show(char array[], int size)
{
for (int i = 0; i < size; i++)
std::cout << array[i];
cout << endl;
}
void BSort(char array[], int size)
{
for (int i = 0; i < size-1; i++)
{
if (array[i] > array[i+1])
{
char temp = array[i+1];
array[i+1] = array[i];
array[i] = temp;
i = -1;
}
}
}
int main(int argc, char *argv[])
{
string s;
cin>>s;
int n = s.size();
char mychars[n] ;
for (int i = 0; i < n; i++){
mychars[i] = s.at(i);
}
int size = sizeof(mychars)/sizeof(char);
Show(mychars, size);
BSort(mychars, size);
Show(mychars, size);
system("PAUSE");
return EXIT_SUCCESS;
}
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Last edited on
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#include <iostream>
#include <string>
#include <algorithm>
using namespace std;
bool check (char ch){
if(ch < 'a' || ch > 'z' || ch =='a' || ch =='e' || ch =='i' || ch =='o' || ch =='u') return 0;
return 1;
}
int main() {
string s = "ebddfff23E";
string s2, s3;
int i=0;
while(i < s.size()){
if(check(s[i])) s2 += s[i];
else s3 += s[i];
i++;
}
std::sort(s2.begin(), s2.end());
cout << s2 << s3;
}
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@anup30
thank you :)
another method.
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#include <iostream>
#include <algorithm>
int main() {
std::string s = "ebddfff23E";
int i, cur;
for(i=s.size()-1, cur=i; i>=0; i--){
if(s[i]<'a'||s[i]>'z'||s[i]=='a'||s[i]=='e'||s[i]=='i'||s[i]=='o'||s[i]=='u'){
std::swap(s[i], s[cur--]);
}
}
std::sort(s.begin(), s.begin()+cur);
std::cout << s;
}
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