Constructor

[kenryuakuma]

class Myclass {
  int x;
  public Myclass (int y) {
    cout << "This is great";
    x = y;
  }

int main () {
  Myclass hold = new Myclass(1);
  
  cout << hold.x;
...

// output
This is great
1

Question: How can the constructor display the message "This is great"? What I know is that everything is executed within the main function or the class with the main function. So I think the object invokes the constructor along with the message, but when does the message occur? After assigning the reference to the Myclass hold variable or something?

[S6k9GNh0]

class Myclass 
{
   public:
   
      int x;
      Myclass (int y) : x(y){ cout << "This is great"; } //Use initialization lists.
      ~Myclass () { cout << "This is great"; } //output This is great in deconstructor
}

int main () 
{
   Myclass *hold = new Myclass(1); //new produces a pointer to the newly allocated memory. You need a pointer.
  
   cout << hold->x;
   
   delete hold; // calls the deconstructor of the class.
}

[kenryuakuma]

Well...Would you please explain why and answer my question? Forget about the destructor as I have not really mastered the use of it.

[Bazzy]

How can the constructor display the message "This is great"?
The code within the constructor is called any time an object is constructed ( when an automatic variable is initialized or when a dynamic one is allocated with new )

[firedraco]

It is output when you construct the object (when you call new).

FYI, the output would actually be:

This is great1

since there is no \n in your couts.

[kenryuakuma]

Thanks bazzy and firedraco and now it clear it up.