This is the question:
Your program should:
1. Ask the user for an integer greater than zero.
2. Call a recursive function that calculates the sum of pairs* of digits.
3. Output what those pairs* are and the sum.
*Break up the pairs as follows in these examples: 123 -> 1+23=24, 1234->12+34=46,
12345->1+23+45=69
CAN SOMEONE PLEASE HELP ME?
I have never done programming before
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#include <iostream>
usingnamespace std;
int sum(int x) {
if (x < 10) return x;
return x % 10 + sum(x / 10);
}
int main() {
int n;
cout << "Enter a number greater than 0: ";
cin >> n;
cout << "The digit sum is " << sum(n) << endl;
return 0;
}
You are summing individual digits instead of pairs of digits. Your code is close, you just need to change a single number in three places. Focus on lines 5 and 6.
Ok so I got that part. I just forgot to change it but I saw that.
I am not sure how to approach the print part
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#include <iostream>
usingnamespace std;
int sum(int x) {
if (x < 100) return x;
return x%100 + sum(x/100);
}
int main() {
int n;
cout << "Please enter a number greater than 0: ";
cin >> n;
cout << "The digit sum is " << sum(n) << endl;
return 0;
}
int main() {
int n;
cout << "Please enter a number greater than 0: ";
cin >> n;
int num=n;
int s=sum(n);
int r1=0, r2=0, r3=0;
r1=n/100;
r2=n%100;
cout << "The sum of the pairs of digits is " << endl;
cout << num << " -> " << r1 << "+" << r2 << "+" << r3 << "=" << sum(n);
cout << endl;
return 0;
}
This is the output I am getting
Please enter a number greater than 0: 12345
The sum of the pairs of digits is
12345 -> 123+45+0=69