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Creating binary from array

EightBitHopes (27)
Hello guys.I need to write a program that "transforms" the input array into a binary code.So far, so great.My only problem is that I know how to make it show the decimal code, I can't figure out how to make it "transform" into binary .. can you guys help ? I've written a comment to the matching line.

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#include<iostream>
#include<string.h>
#include<math.h>
using namespace std;
int main()
{
    char bin[50];
    cout<<"Input the array : ";
    cin>>bin;
    cin.ignore(1);
    int number=0;
    int p=strlen(bin)-1;
    for(int i=p;i>=0;i--)
    number+=(bin[i]-48)*(int)pow(2,(p-i)); //The only problematic line.
    cout<<number<<endl;
    system("pause");
    return 0;
}
Smac89 (1727)
That line shows that you are converting from binary to decimal...where have you attempted to convert from decimal to binary?
EightBitHopes (27)
That's the thing I don't know how to convert the input array to binary ..
TarikNeaj (2580)
alexBB (131)
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