Writing a function with void paramter

[joshuatz]

For my assignment I have to do use a previous assignment I did and break it into the following functions:

// get the number of rows from the user, assuring legal and odd,
// then return it to the caller
int GetNRows( void );

There are others I have to write a functions that I need to write for this problem, but I'm really stuck on this first function. When I compile it I get an error that says: "error: expected primary-expression before 'int'" and "error: expected ';' before 'int'" I'm not really sure if I'm approaching this correctly or not. Thank you in advance for your help!

  #include<iostream>
using namespace std;

int GetNRows()
{
    int nRows;
    cout << "Enter nRows: " << flush;
    cin >> nRows;
    return nRows;
}
int main()
{
    int nRows;
    nRows=int GetNRows();
    return 0;
}

[xenovia12]

nRows =int GetNRows();
when you call a function you dont need to include its type

[joshuatz]

Also I forgot to mention that inside where you put the parameters it is void so it's int GetNRows(void) also if I return it to caller where should I return it?

[TarikNeaj]

void parameter means no parameters.

int GetNRows() thats already a void parameter.

void = nothing. Just change this nRows=int GetNRows(); to this nRows = getNRows();

And your function is done. You are already returning rows. return nRows;

And saving it in nRows back in main.

[SECMoG1T]

And just to mention type function(void) are mostly used for backward compatibility with 'C' language so they maybe necessary if Op want's to maintain that but not required in plain c++.

[joshuatz]

If it's okay, I sent you(andy1992) a PM of my program and I'm hoping you can look at it when you get the chance. Thanks for the advice! Sorry for the disturbance.