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thanks

justhappy (35)
thankyou
Last edited on
TarikNeaj (2580)
Becuase you literally only tell it to output the last word. 

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case 'E': case 'e':
outputString = +"Echo";
break;
case 'F': case 'f':
outputString = +"Foxtrot";
break;
case 'G': case 'g':
outputString = +"Golf";
break;


If case E, output Echo, if case F, output Foxtrot etc
justhappy (35)
.....
Last edited on
amirtork (48)
Hi,
you can use .insert(site_t size, const &string) instaid of '+' operator, because '+' will erase any data it was stored in that string before and store new string in it, Or, if you want use operators, i suggest use '+=' operator, it will do what you want ;)

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#include <iostream>
#include <string>
using namespace std;

int main ()
{
// declare variables
string inputString;
string outputString=" ";
char inChar;

//enter a string prompt
cout << "Enter string: ";
cin >> inputString;

//designation of length of string and beginning of loop
for (int i = 0; i < inputString.length (); i++)
{
// recalling input string
inChar = inputString.at (i);

int length = outputString.length();
//get corresponding icao word to char, allowing strings
switch (inChar)
{
case 'A': case 'a':
outputString.insert(length, " Alpha");
break;
case 'B': case 'b':
outputString.insert(length, " Bravo");
break;
case 'C': case 'c':
outputString.insert(length, " Charlie");
break;
case 'D': case 'd':
outputString.insert(length, " Delta");
break;
case 'E': case 'e':
outputString.insert(length, " Echo");
break;
case 'F': case 'f':
outputString.insert(length, " Foxtrot");
break;
case 'G': case 'g':
outputString.insert(length, " Golf");
break;
case 'H': case 'h':
outputString.insert(length, " Hotel");
break;
case 'I': case 'i':
outputString.insert(length, " India");
break;
case 'J': case 'j':
outputString.insert(length, " Juliet");
break;
case 'K': case 'k':
outputString.insert(length, " Kilo");
break;
case 'L': case 'l':
outputString.insert(length, " Lima");
break;
case 'M': case 'm':
outputString.insert(length, " Mike");
break;
case 'N': case 'n':
outputString.insert(length, " November");
break;
case 'O': case 'o':
outputString.insert(length, " Oscar");
break;
case 'P': case 'p':
outputString.insert(length, " Papa");
break;
case 'Q': case 'q':
outputString.insert(length, " Quebec");
break;
case 'R': case 'r' :
outputString.insert(length, " Romeo");
break;
case 'S': case 's' :
outputString.insert(length, " Sierra");
break;
case 'T': case 't' :
outputString.insert(length, " Tango");
break;
case 'U': case 'u' :
outputString.insert(length, " Uniform");
break;
case 'V': case 'v' :
outputString.insert(length, " Victor");
break;
case 'W': case 'w' :
outputString.insert(length, " Whiskey");
break;
case 'X': case 'x' :
outputString.insert(length, " X-ray");
break;
case 'Y': case 'y' :
outputString.insert(length, " Yankee");
break;
case 'Z': case 'z':
outputString.insert(length, " Zulu");
break;
}
}
cout << "The phonetic version is:" << outputString << endl;

system ("pause");
return 0;
}
Last edited on
TarikNeaj (2580)
The problem is, that your plus sign is on the wrong spot. In all cases, change it from this -

outputString = +"Delta";

to this

outputString += "Delta "; // dont forget the space after the word

And that will make you a happy person.

Edit:
To clarify more. What you're trying to do is Take the current string, add the new string, and put it all combined in the current string (bad explanation but hope you got it) the way of doing it is like this outputString = outputString = "Delta";

Which is exactly what outputString += "Delta "; does, its just a shorter way of doing it.
Last edited on
justhappy (35)
This works really well. Thank you both. :)
Last edited on
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