error C2059: syntax error : 'return'
Mar 13, 2015 at 9:54pm UTC
Hey guys, I'm relatively new to c++ , and I'm having trouble with my program I'm writing. It's supposed to ask user input for squares and rectangles, but it's not compiling right. Any kind of help or hints would be very much appreciated. Thanks in advance.
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#include <iostream>
using namespace std;
void DisplayMenu()
{
cout << "Main Menu" << endl << endl;
cout << "1. Draw a square" << endl;
cout << "2. Draw a rectangle" << endl;
cout << "3. Quit the program" << endl;
}
int GetUserMenuChoice()
{
int menuChoice = 0;
do
{
DisplayMenu();
cin >> menuChoice;
if (menuChoice < 1 || menuChoice > 3)
{
cout << "Please enter a valid menu choice: " ;
cin >> menuChoice;
}
else
{
cout << "You entered: " << menuChoice << endl << endl;
}
}
return ;
}
int GetSize()
{
int size = 0;
do
{
cout << "Enter a size value from 1-10: " ;
cin >> size;
if (size < 1 || size > 10)
{
cout << "Please enter a valid size value: " ;
cin >> size;
}
else
{
cout << "You entered: " << size << endl << endl;
}
}
return ;
}
int GetHeight()
{
int height = 0;
do
{
cout << "Enter a height value from 1-10: " ;
cin >> height;
if (height < 1 || height > 10)
{
cout << "Please enter a valid height value: " ;
cin >> height;
}
else
{
cout << "You entered: " << height << endl << endl;
}
}
return ;
}
int GetWidth()
{
int width = 0;
do
{
cout << "Enter a width value from 1-10: " ;
cin >> width;
if (width < 1 || width > 10)
{
cout << "Please enter a valid width value: " ;
cin >> width;
}
else
{
cout << "You entered: " << width << endl << endl;
}
}
return ;
}
void DisplaySquare(int size)
{
{
int row = 0;
int col = 0;
for (col = 1; col <= size; col++)
{
cout << endl << endl;
for (row = 1; row <= size; row++)
{
cout << " * " ;
}
}
system("pause" );
}
}
void DisplayRectangle(int height, int width)
{
{
int row = 0;
int col = 0;
for (col = 1; col <= height; col++)
{
cout << endl << endl;
for (row = 1; row <= width; row++)
{
cout << " * " ;
}
}
system("pause" );
}
}
int main()
{
int menuChoice = 0, size = 0, height = 0, width = 0;
while (menuChoice != 3)
{
menuChoice = GetUserMenuChoice();
switch (menuChoice)
{
case 1: // Draw a square
size = GetSize();
DisplaySquare(size);
break ;
case 2: // Draw a rectangle
height = GetHeight();
width = GetWidth();
DisplayRectangle(height, width);
break ;
case 3: // Quit the program
cout << "Quitting program!" << endl;
break ;
}
}
return 0;
}
The errors I am getting are:
error C2059: syntax error : 'return'
error C2059: syntax error : 'return'
error C2059: syntax error : 'return'
I'm not sure if I formatted the code right since it's my first time posting here, I will fix it if it didn't.
Mar 13, 2015 at 10:00pm UTC
You never return anything in any of your functions. For example -
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int GetUserMenuChoice()
{
int menuChoice = 0;
do
{
DisplayMenu();
cin >> menuChoice;
if (menuChoice < 1 || menuChoice > 3)
{
cout << "Please enter a valid menu choice: " ;
cin >> menuChoice;
}
else
{
cout << "You entered: " << menuChoice << endl << endl;
}
}
return ;
}
You want to return the menu choice right? Ofc you do! You then have to return it like this -
return menuChoice;
Then in main -
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menuChoice = GetUserMenuChoice();
switch (menuChoice)
If say, the user chooses menu option 2. menuChoice will be equal to 2. Which works fine :)
Mar 13, 2015 at 10:04pm UTC
Oops, I forgot to type those in. I was in the middle of trying to figure it out.
I did however get the program to work. Just needed to get rid of the do {}, it was unnecessary.
Thanks for the help!
Mar 13, 2015 at 10:05pm UTC
Glad it worked out :)
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