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Printing 2D Array Using Pointers

Jweim (28)
In my program below, I'm having an issue. I can't seem to pass the 2D array "expenses" to the function by pointer (required to do it this way) "displayExpenses" and then print the contents of the 2D array. What ends up printing are two rows of "1234567". I've been looking at this for a few hours and just wan to have someone else see if they can tell what I'm not doing right.

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#include <iostream>
#include <string>
#include <iomanip>
#include <cctype>

using namespace std;

//Structure-------------------------------
struct Day_t
{
    string day;
};


//Function Prototypes---------------------
void displayMenu();
void displayExpenses(int *, Day_t[]);
void sortExpenses(int *, Day_t[]);
void searchExpenses(int *, Day_t[]);

int main() {
    
    int expenses[2][7];
    
    Day_t week[7];
    week[0].day = "Monday", week[1].day = "Tuesday", week[2].day = "Wednesday", week[3].day = "Thursday", week[4].day = "Friday", week[5].day = "Saturday", week[6].day = "Sunday";
    
    
    //Input Data for 2D Array [2][7]-------
    for (int i = 0; i < 2; i++)
    {
        for (int j = 0; j < 7; j++)
        {
            cout << "Enter expenses for week " << i + 1 << ", day " << j + 1 << ": ";
            cin >> expenses[i][j];
        }
        cout << endl;
    }
    
    //Display Main Menu for Select Options----------------
    displayMenu();
    
    char selection = 'z';
    bool quit = false;
    
    while (!quit)
    {
        
        cout << "Please enter your selection: \n";
        cin >> selection;
        
        switch (selection)
        {
                
            case '1': displayExpenses(*expenses, week);
                break;
                
            //case '2': sortExpenses(*expenses, week);
                break;
                
            //case '3': searchExpenses(*expenses, week);
                break;
                
            case '5': quit = true;
                break;
                
            default: cout << "You did not enter a valid input. Please enter a number 1-5..." << endl;
        }
    }
    
    return 0;
}


void displayMenu()
{
    cout << "\t Two-Week Expense Report\n"
    << "Enter 1 to display the data\n" //1 function
    << "Enter 2 to sort expenses in ascending order\n" //2 function
    << "Enter 3 to search for largest expense\n" //3 function
    << "Enter 5 to exit\n\n";
}

void displayExpenses(int *arr, Day_t week[])
{
    
    for (int x = 0; x < 7; x++)
    {
        cout << week[x].day << " ";
    }
    cout << endl;
    
    for (int i = 0; i < 2; i++)
    {
        for (int j = 0; j < 7; j++)
        {
            cout << (*(arr + i)+j);
        }
        cout << endl;
    }
    
}

void sortExpenses(int *arr, Day_t week[])
{
    
}

void searchExpenses(int *arr, Day_t week[])
{
    
    
}
Justin33 (8)
 
 
cout << (*(arr + i)+j);

should be changed to 
1
2
 
cout << (*(arr + i*7)+j);
Jweim (28)
@Justin33 that actually still justs prints out "1234567"

Though, I did finally figure out a way to do it...

 
 
cout << *((arr + i)+j);
Justin33 (8)

 
 
cout << *(arr + i*7+j);
Justin33 (8)
This line may also need changing.
case '1': displayExpenses(*expenses, week);

Try :
case '1': displayExpenses(expenses, week);
Jweim (28)
@Justion33, thanks the updated syntax worked. I initially had my code written like yours above, however, Xcode keeps giving me compiler errors saying there are no matching function calls. I couldn't find a reason why, so I left the function call with the pointer included.
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